4x^2-x+8=-2x+11

Solution for 4x^2-x+8=-2x+11 equation:

4x^2-x+8=-2x+11

We move all terms to the left:

4x^2-x+8-(-2x+11)=0

We add all the numbers together, and all the variables

4x^2-1x-(-2x+11)+8=0

We get rid of parentheses

4x^2-1x+2x-11+8=0

We add all the numbers together, and all the variables

4x^2+x-3=0

a = 4; b = 1; c = -3;
Δ = b2-4ac
Δ = 12-4·4·(-3)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-7}{2*4}=\frac{-8}{8}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+7}{2*4}=\frac{6}{8}
=3/4
$